3.1.57 \(\int \frac {(c+d x)^3}{(a+b \cot (e+f x))^2} \, dx\) [57]

3.1.57.1 Optimal result
3.1.57.2 Mathematica [B] (warning: unable to verify)
3.1.57.3 Rubi [A] (verified)
3.1.57.4 Maple [B] (verified)
3.1.57.5 Fricas [B] (verification not implemented)
3.1.57.6 Sympy [F]
3.1.57.7 Maxima [B] (verification not implemented)
3.1.57.8 Giac [F]
3.1.57.9 Mupad [F(-1)]

3.1.57.1 Optimal result

Integrand size = 20, antiderivative size = 839 \[ \int \frac {(c+d x)^3}{(a+b \cot (e+f x))^2} \, dx=-\frac {2 i b^2 (c+d x)^3}{\left (a^2+b^2\right )^2 f}-\frac {2 b^2 (c+d x)^3}{(a-i b) (a+i b)^2 \left (i a+b-(i a-b) e^{2 i e+2 i f x}\right ) f}+\frac {(c+d x)^4}{4 (a+i b)^2 d}-\frac {b (c+d x)^4}{(a+i b)^2 (i a+b) d}-\frac {b^2 (c+d x)^4}{\left (a^2+b^2\right )^2 d}+\frac {3 b^2 d (c+d x)^2 \log \left (1-\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{\left (a^2+b^2\right )^2 f^2}-\frac {2 b (c+d x)^3 \log \left (1-\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{(a-i b) (a+i b)^2 f}-\frac {2 i b^2 (c+d x)^3 \log \left (1-\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{\left (a^2+b^2\right )^2 f}-\frac {3 i b^2 d^2 (c+d x) \operatorname {PolyLog}\left (2,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{\left (a^2+b^2\right )^2 f^3}-\frac {3 b d (c+d x)^2 \operatorname {PolyLog}\left (2,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{(a+i b)^2 (i a+b) f^2}-\frac {3 b^2 d (c+d x)^2 \operatorname {PolyLog}\left (2,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{\left (a^2+b^2\right )^2 f^2}+\frac {3 b^2 d^3 \operatorname {PolyLog}\left (3,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{2 \left (a^2+b^2\right )^2 f^4}-\frac {3 b d^2 (c+d x) \operatorname {PolyLog}\left (3,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{(a-i b) (a+i b)^2 f^3}-\frac {3 i b^2 d^2 (c+d x) \operatorname {PolyLog}\left (3,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{\left (a^2+b^2\right )^2 f^3}+\frac {3 b d^3 \operatorname {PolyLog}\left (4,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{2 (a+i b)^2 (i a+b) f^4}+\frac {3 b^2 d^3 \operatorname {PolyLog}\left (4,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{2 \left (a^2+b^2\right )^2 f^4} \]

output
-2*I*b^2*(d*x+c)^3/(a^2+b^2)^2/f-2*b^2*(d*x+c)^3/(a-I*b)/(a+I*b)^2/(I*a+b- 
(I*a-b)*exp(2*I*e+2*I*f*x))/f+1/4*(d*x+c)^4/(a+I*b)^2/d-b*(d*x+c)^4/(a+I*b 
)^2/(I*a+b)/d-b^2*(d*x+c)^4/(a^2+b^2)^2/d+3*b^2*d*(d*x+c)^2*ln(1-(a+I*b)*e 
xp(2*I*e+2*I*f*x)/(a-I*b))/(a^2+b^2)^2/f^2-2*b*(d*x+c)^3*ln(1-(a+I*b)*exp( 
2*I*e+2*I*f*x)/(a-I*b))/(a-I*b)/(a+I*b)^2/f-2*I*b^2*(d*x+c)^3*ln(1-(a+I*b) 
*exp(2*I*e+2*I*f*x)/(a-I*b))/(a^2+b^2)^2/f-3*I*b^2*d^2*(d*x+c)*polylog(3,( 
a+I*b)*exp(2*I*e+2*I*f*x)/(a-I*b))/(a^2+b^2)^2/f^3-3*b*d*(d*x+c)^2*polylog 
(2,(a+I*b)*exp(2*I*e+2*I*f*x)/(a-I*b))/(a+I*b)^2/(I*a+b)/f^2-3*b^2*d*(d*x+ 
c)^2*polylog(2,(a+I*b)*exp(2*I*e+2*I*f*x)/(a-I*b))/(a^2+b^2)^2/f^2+3/2*b^2 
*d^3*polylog(3,(a+I*b)*exp(2*I*e+2*I*f*x)/(a-I*b))/(a^2+b^2)^2/f^4-3*b*d^2 
*(d*x+c)*polylog(3,(a+I*b)*exp(2*I*e+2*I*f*x)/(a-I*b))/(a-I*b)/(a+I*b)^2/f 
^3-3*I*b^2*d^2*(d*x+c)*polylog(2,(a+I*b)*exp(2*I*e+2*I*f*x)/(a-I*b))/(a^2+ 
b^2)^2/f^3+3/2*b*d^3*polylog(4,(a+I*b)*exp(2*I*e+2*I*f*x)/(a-I*b))/(a+I*b) 
^2/(I*a+b)/f^4+3/2*b^2*d^3*polylog(4,(a+I*b)*exp(2*I*e+2*I*f*x)/(a-I*b))/( 
a^2+b^2)^2/f^4
 
3.1.57.2 Mathematica [B] (warning: unable to verify)

Both result and optimal contain complex but leaf count is larger than twice the leaf count of optimal. \(1733\) vs. \(2(839)=1678\).

Time = 11.55 (sec) , antiderivative size = 1733, normalized size of antiderivative = 2.07 \[ \int \frac {(c+d x)^3}{(a+b \cot (e+f x))^2} \, dx =\text {Too large to display} \]

input
Integrate[(c + d*x)^3/(a + b*Cot[e + f*x])^2,x]
 
output
(b*((4*c^2*(a*(-1 + E^((2*I)*e)) + I*b*(1 + E^((2*I)*e)))*(-3*b*d + 2*a*c* 
f)*x)/(a^2 + b^2) - (4*b*(c + d*x)^3)/(a + I*b) + (2*a*f*(c + d*x)^4)/((a 
+ I*b)*d) + (12*c*d*(a*(-1 + E^((2*I)*e)) + I*b*(1 + E^((2*I)*e)))*(-(b*d) 
 + a*c*f)*x*Log[1 + (-a + I*b)/((a + I*b)*E^((2*I)*(e + f*x)))])/((a - I*b 
)*((-I)*a + b)*f) - (6*d^2*(a*(-1 + E^((2*I)*e)) + I*b*(1 + E^((2*I)*e)))* 
(b*d - 2*a*c*f)*x^2*Log[1 + (-a + I*b)/((a + I*b)*E^((2*I)*(e + f*x)))])/( 
(a - I*b)*((-I)*a + b)*f) + (4*a*d^3*(a*(-1 + E^((2*I)*e)) + I*b*(1 + E^(( 
2*I)*e)))*x^3*Log[1 + (-a + I*b)/((a + I*b)*E^((2*I)*(e + f*x)))])/((a - I 
*b)*((-I)*a + b)) + (2*c^2*(a*(-1 + E^((2*I)*e)) + I*b*(1 + E^((2*I)*e)))* 
(-3*b*d + 2*a*c*f)*Log[a - I*b - (a + I*b)*E^((2*I)*(e + f*x))])/((a - I*b 
)*((-I)*a + b)*f) - (6*c*d*(a*(-1 + E^((2*I)*e)) + I*b*(1 + E^((2*I)*e)))* 
(-(b*d) + a*c*f)*PolyLog[2, (a - I*b)/((a + I*b)*E^((2*I)*(e + f*x)))])/(( 
a^2 + b^2)*f^2) + (3*d^2*(a*(-1 + E^((2*I)*e)) + I*b*(1 + E^((2*I)*e)))*(b 
*d - 2*a*c*f)*(2*f*x*PolyLog[2, (a - I*b)/((a + I*b)*E^((2*I)*(e + f*x)))] 
 - I*PolyLog[3, (a - I*b)/((a + I*b)*E^((2*I)*(e + f*x)))]))/((a^2 + b^2)* 
f^3) - (3*a*d^3*(a*(-1 + E^((2*I)*e)) + I*b*(1 + E^((2*I)*e)))*(2*f^2*x^2* 
PolyLog[2, (a - I*b)/((a + I*b)*E^((2*I)*(e + f*x)))] - (2*I)*f*x*PolyLog[ 
3, (a - I*b)/((a + I*b)*E^((2*I)*(e + f*x)))] - PolyLog[4, (a - I*b)/((a + 
 I*b)*E^((2*I)*(e + f*x)))]))/((a^2 + b^2)*f^3)))/(2*(a - I*b)*(a + I*b)*( 
(-I)*a*(-1 + E^((2*I)*e)) + b*(1 + E^((2*I)*e)))*f) + (3*x^2*(-(a*c^2*d...
 
3.1.57.3 Rubi [A] (verified)

Time = 2.21 (sec) , antiderivative size = 839, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {3042, 4217, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(c+d x)^3}{(a+b \cot (e+f x))^2} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {(c+d x)^3}{\left (a-b \tan \left (e+f x+\frac {\pi }{2}\right )\right )^2}dx\)

\(\Big \downarrow \) 4217

\(\displaystyle \int \left (-\frac {4 b^2 (c+d x)^3}{(-b+i a)^2 \left (i a \left (1-\frac {i b}{a}\right )-i a \left (1+\frac {i b}{a}\right ) e^{2 i e+2 i f x}\right )^2}+\frac {4 b (c+d x)^3}{(a+i b)^2 \left (i a \left (1+\frac {i b}{a}\right ) e^{2 i e+2 i f x}-i a \left (1-\frac {i b}{a}\right )\right )}+\frac {(c+d x)^3}{(a+i b)^2}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle -\frac {b (c+d x)^4}{(a+i b)^2 (i a+b) d}+\frac {(c+d x)^4}{4 (a+i b)^2 d}-\frac {b^2 (c+d x)^4}{\left (a^2+b^2\right )^2 d}-\frac {2 b \log \left (1-\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right ) (c+d x)^3}{(a-i b) (a+i b)^2 f}-\frac {2 i b^2 \log \left (1-\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right ) (c+d x)^3}{\left (a^2+b^2\right )^2 f}-\frac {2 b^2 (c+d x)^3}{(a-i b) (a+i b)^2 \left (i a-(i a-b) e^{2 i e+2 i f x}+b\right ) f}-\frac {2 i b^2 (c+d x)^3}{\left (a^2+b^2\right )^2 f}+\frac {3 b^2 d \log \left (1-\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right ) (c+d x)^2}{\left (a^2+b^2\right )^2 f^2}-\frac {3 b d \operatorname {PolyLog}\left (2,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right ) (c+d x)^2}{(a+i b)^2 (i a+b) f^2}-\frac {3 b^2 d \operatorname {PolyLog}\left (2,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right ) (c+d x)^2}{\left (a^2+b^2\right )^2 f^2}-\frac {3 i b^2 d^2 \operatorname {PolyLog}\left (2,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right ) (c+d x)}{\left (a^2+b^2\right )^2 f^3}-\frac {3 b d^2 \operatorname {PolyLog}\left (3,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right ) (c+d x)}{(a-i b) (a+i b)^2 f^3}-\frac {3 i b^2 d^2 \operatorname {PolyLog}\left (3,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right ) (c+d x)}{\left (a^2+b^2\right )^2 f^3}+\frac {3 b^2 d^3 \operatorname {PolyLog}\left (3,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{2 \left (a^2+b^2\right )^2 f^4}+\frac {3 b d^3 \operatorname {PolyLog}\left (4,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{2 (a+i b)^2 (i a+b) f^4}+\frac {3 b^2 d^3 \operatorname {PolyLog}\left (4,\frac {(a+i b) e^{2 i e+2 i f x}}{a-i b}\right )}{2 \left (a^2+b^2\right )^2 f^4}\)

input
Int[(c + d*x)^3/(a + b*Cot[e + f*x])^2,x]
 
output
((-2*I)*b^2*(c + d*x)^3)/((a^2 + b^2)^2*f) - (2*b^2*(c + d*x)^3)/((a - I*b 
)*(a + I*b)^2*(I*a + b - (I*a - b)*E^((2*I)*e + (2*I)*f*x))*f) + (c + d*x) 
^4/(4*(a + I*b)^2*d) - (b*(c + d*x)^4)/((a + I*b)^2*(I*a + b)*d) - (b^2*(c 
 + d*x)^4)/((a^2 + b^2)^2*d) + (3*b^2*d*(c + d*x)^2*Log[1 - ((a + I*b)*E^( 
(2*I)*e + (2*I)*f*x))/(a - I*b)])/((a^2 + b^2)^2*f^2) - (2*b*(c + d*x)^3*L 
og[1 - ((a + I*b)*E^((2*I)*e + (2*I)*f*x))/(a - I*b)])/((a - I*b)*(a + I*b 
)^2*f) - ((2*I)*b^2*(c + d*x)^3*Log[1 - ((a + I*b)*E^((2*I)*e + (2*I)*f*x) 
)/(a - I*b)])/((a^2 + b^2)^2*f) - ((3*I)*b^2*d^2*(c + d*x)*PolyLog[2, ((a 
+ I*b)*E^((2*I)*e + (2*I)*f*x))/(a - I*b)])/((a^2 + b^2)^2*f^3) - (3*b*d*( 
c + d*x)^2*PolyLog[2, ((a + I*b)*E^((2*I)*e + (2*I)*f*x))/(a - I*b)])/((a 
+ I*b)^2*(I*a + b)*f^2) - (3*b^2*d*(c + d*x)^2*PolyLog[2, ((a + I*b)*E^((2 
*I)*e + (2*I)*f*x))/(a - I*b)])/((a^2 + b^2)^2*f^2) + (3*b^2*d^3*PolyLog[3 
, ((a + I*b)*E^((2*I)*e + (2*I)*f*x))/(a - I*b)])/(2*(a^2 + b^2)^2*f^4) - 
(3*b*d^2*(c + d*x)*PolyLog[3, ((a + I*b)*E^((2*I)*e + (2*I)*f*x))/(a - I*b 
)])/((a - I*b)*(a + I*b)^2*f^3) - ((3*I)*b^2*d^2*(c + d*x)*PolyLog[3, ((a 
+ I*b)*E^((2*I)*e + (2*I)*f*x))/(a - I*b)])/((a^2 + b^2)^2*f^3) + (3*b*d^3 
*PolyLog[4, ((a + I*b)*E^((2*I)*e + (2*I)*f*x))/(a - I*b)])/(2*(a + I*b)^2 
*(I*a + b)*f^4) + (3*b^2*d^3*PolyLog[4, ((a + I*b)*E^((2*I)*e + (2*I)*f*x) 
)/(a - I*b)])/(2*(a^2 + b^2)^2*f^4)
 

3.1.57.3.1 Defintions of rubi rules used

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4217
Int[((c_.) + (d_.)*(x_))^(m_.)*((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(n_), 
 x_Symbol] :> Int[ExpandIntegrand[(c + d*x)^m, (1/(a - I*b) - 2*I*(b/(a^2 + 
 b^2 + (a - I*b)^2*E^(2*I*(e + f*x)))))^(-n), x], x] /; FreeQ[{a, b, c, d, 
e, f}, x] && NeQ[a^2 + b^2, 0] && ILtQ[n, 0] && IGtQ[m, 0]
 
3.1.57.4 Maple [B] (verified)

Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 5930 vs. \(2 (754 ) = 1508\).

Time = 0.78 (sec) , antiderivative size = 5931, normalized size of antiderivative = 7.07

method result size
risch \(\text {Expression too large to display}\) \(5931\)

input
int((d*x+c)^3/(a+b*cot(f*x+e))^2,x,method=_RETURNVERBOSE)
 
output
result too large to display
 
3.1.57.5 Fricas [B] (verification not implemented)

Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 3363 vs. \(2 (687) = 1374\).

Time = 0.38 (sec) , antiderivative size = 3363, normalized size of antiderivative = 4.01 \[ \int \frac {(c+d x)^3}{(a+b \cot (e+f x))^2} \, dx=\text {Too large to display} \]

input
integrate((d*x+c)^3/(a+b*cot(f*x+e))^2,x, algorithm="fricas")
 
output
1/4*((a^2*b - b^3)*d^3*f^4*x^4 - 4*a*b^2*c^3*f^3 - 4*(a*b^2*d^3*f^3 - (a^2 
*b - b^3)*c*d^2*f^4)*x^3 - 6*(2*a*b^2*c*d^2*f^3 - (a^2*b - b^3)*c^2*d*f^4) 
*x^2 - 4*(3*a*b^2*c^2*d*f^3 - (a^2*b - b^3)*c^3*f^4)*x + ((a^2*b - b^3)*d^ 
3*f^4*x^4 - 4*a*b^2*c^3*f^3 - 4*(a*b^2*d^3*f^3 - (a^2*b - b^3)*c*d^2*f^4)* 
x^3 - 6*(2*a*b^2*c*d^2*f^3 - (a^2*b - b^3)*c^2*d*f^4)*x^2 - 4*(3*a*b^2*c^2 
*d*f^3 - (a^2*b - b^3)*c^3*f^4)*x)*cos(2*f*x + 2*e) - 6*(-I*a*b^2*d^3*f^2* 
x^2 - I*a*b^2*c^2*d*f^2 + I*b^3*c*d^2*f - I*(2*a*b^2*c*d^2*f^2 - b^3*d^3*f 
)*x + (-I*a*b^2*d^3*f^2*x^2 - I*a*b^2*c^2*d*f^2 + I*b^3*c*d^2*f - I*(2*a*b 
^2*c*d^2*f^2 - b^3*d^3*f)*x)*cos(2*f*x + 2*e) + (-I*a^2*b*d^3*f^2*x^2 - I* 
a^2*b*c^2*d*f^2 + I*a*b^2*c*d^2*f - I*(2*a^2*b*c*d^2*f^2 - a*b^2*d^3*f)*x) 
*sin(2*f*x + 2*e))*dilog(-(a^2 + b^2 - (a^2 + 2*I*a*b - b^2)*cos(2*f*x + 2 
*e) + (-I*a^2 + 2*a*b + I*b^2)*sin(2*f*x + 2*e))/(a^2 + b^2) + 1) - 6*(I*a 
*b^2*d^3*f^2*x^2 + I*a*b^2*c^2*d*f^2 - I*b^3*c*d^2*f + I*(2*a*b^2*c*d^2*f^ 
2 - b^3*d^3*f)*x + (I*a*b^2*d^3*f^2*x^2 + I*a*b^2*c^2*d*f^2 - I*b^3*c*d^2* 
f + I*(2*a*b^2*c*d^2*f^2 - b^3*d^3*f)*x)*cos(2*f*x + 2*e) + (I*a^2*b*d^3*f 
^2*x^2 + I*a^2*b*c^2*d*f^2 - I*a*b^2*c*d^2*f + I*(2*a^2*b*c*d^2*f^2 - a*b^ 
2*d^3*f)*x)*sin(2*f*x + 2*e))*dilog(-(a^2 + b^2 - (a^2 - 2*I*a*b - b^2)*co 
s(2*f*x + 2*e) + (I*a^2 + 2*a*b - I*b^2)*sin(2*f*x + 2*e))/(a^2 + b^2) + 1 
) + 2*(2*a*b^2*d^3*e^3 - 2*a*b^2*c^3*f^3 + 3*b^3*d^3*e^2 + 3*(2*a*b^2*c^2* 
d*e + b^3*c^2*d)*f^2 - 6*(a*b^2*c*d^2*e^2 + b^3*c*d^2*e)*f + (2*a*b^2*d...
 
3.1.57.6 Sympy [F]

\[ \int \frac {(c+d x)^3}{(a+b \cot (e+f x))^2} \, dx=\int \frac {\left (c + d x\right )^{3}}{\left (a + b \cot {\left (e + f x \right )}\right )^{2}}\, dx \]

input
integrate((d*x+c)**3/(a+b*cot(f*x+e))**2,x)
 
output
Integral((c + d*x)**3/(a + b*cot(e + f*x))**2, x)
 
3.1.57.7 Maxima [B] (verification not implemented)

Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 4641 vs. \(2 (687) = 1374\).

Time = 3.18 (sec) , antiderivative size = 4641, normalized size of antiderivative = 5.53 \[ \int \frac {(c+d x)^3}{(a+b \cot (e+f x))^2} \, dx=\text {Too large to display} \]

input
integrate((d*x+c)^3/(a+b*cot(f*x+e))^2,x, algorithm="maxima")
 
output
1/12*(36*(b^2/((a^4 + a^2*b^2)*f*tan(f*x + e) + (a^3*b + a*b^3)*f) + 2*a*b 
*log(a*tan(f*x + e) + b)/((a^4 + 2*a^2*b^2 + b^4)*f) - a*b*log(tan(f*x + e 
)^2 + 1)/((a^4 + 2*a^2*b^2 + b^4)*f) - (a^2 - b^2)*(f*x + e)/((a^4 + 2*a^2 
*b^2 + b^4)*f))*c^2*d*e - 12*(2*a*b*log(a*tan(f*x + e) + b)/(a^4 + 2*a^2*b 
^2 + b^4) - a*b*log(tan(f*x + e)^2 + 1)/(a^4 + 2*a^2*b^2 + b^4) - (a^2 - b 
^2)*(f*x + e)/(a^4 + 2*a^2*b^2 + b^4) + b^2/(a^3*b + a*b^3 + (a^4 + a^2*b^ 
2)*tan(f*x + e)))*c^3 - (3*(a^3 + I*a^2*b + a*b^2 + I*b^3)*(f*x + e)^4*d^3 
 + 24*(-I*a*b^2 - b^3)*d^3*e^3 + 72*(I*a*b^2 + b^3)*c*d^2*e^2*f - 12*((a^3 
 + I*a^2*b + a*b^2 + I*b^3)*d^3*e - (a^3 + I*a^2*b + a*b^2 + I*b^3)*c*d^2* 
f)*(f*x + e)^3 + 18*((a^3 + I*a^2*b + a*b^2 + I*b^3)*d^3*e^2 - 2*(a^3 + I* 
a^2*b + a*b^2 + I*b^3)*c*d^2*e*f + (a^3 + I*a^2*b + a*b^2 + I*b^3)*c^2*d*f 
^2)*(f*x + e)^2 - 12*((a^3 + I*a^2*b + a*b^2 + I*b^3)*d^3*e^3 - 3*(a^3 + I 
*a^2*b + a*b^2 + I*b^3)*c*d^2*e^2*f)*(f*x + e) + 12*(2*(I*a^2*b + a*b^2)*d 
^3*e^3 + 3*(I*a*b^2 + b^3)*d^3*e^2 + 3*(I*a*b^2 + b^3)*c^2*d*f^2 + 6*((-I* 
a^2*b - a*b^2)*c*d^2*e^2 + (-I*a*b^2 - b^3)*c*d^2*e)*f + (2*(-I*a^2*b + a* 
b^2)*d^3*e^3 + 3*(-I*a*b^2 + b^3)*d^3*e^2 + 3*(-I*a*b^2 + b^3)*c^2*d*f^2 + 
 6*((I*a^2*b - a*b^2)*c*d^2*e^2 + (I*a*b^2 - b^3)*c*d^2*e)*f)*cos(2*f*x + 
2*e) + (2*(a^2*b + I*a*b^2)*d^3*e^3 + 3*(a*b^2 + I*b^3)*d^3*e^2 + 3*(a*b^2 
 + I*b^3)*c^2*d*f^2 - 6*((a^2*b + I*a*b^2)*c*d^2*e^2 + (a*b^2 + I*b^3)*c*d 
^2*e)*f)*sin(2*f*x + 2*e))*arctan2(b*cos(2*f*x + 2*e) + a*sin(2*f*x + 2...
 
3.1.57.8 Giac [F]

\[ \int \frac {(c+d x)^3}{(a+b \cot (e+f x))^2} \, dx=\int { \frac {{\left (d x + c\right )}^{3}}{{\left (b \cot \left (f x + e\right ) + a\right )}^{2}} \,d x } \]

input
integrate((d*x+c)^3/(a+b*cot(f*x+e))^2,x, algorithm="giac")
 
output
integrate((d*x + c)^3/(b*cot(f*x + e) + a)^2, x)
 
3.1.57.9 Mupad [F(-1)]

Timed out. \[ \int \frac {(c+d x)^3}{(a+b \cot (e+f x))^2} \, dx=\int \frac {{\left (c+d\,x\right )}^3}{{\left (a+b\,\mathrm {cot}\left (e+f\,x\right )\right )}^2} \,d x \]

input
int((c + d*x)^3/(a + b*cot(e + f*x))^2,x)
 
output
int((c + d*x)^3/(a + b*cot(e + f*x))^2, x)